You could use
Month class>>#daysInMonth:forYear:
Which I think does what you want already.
stepharo wrote
Hi
I started to write a little utility to generate bills.
And I need to know the number of days in a month and I was surprised that
(Month month: 2) daysInMonth returns 28 because we do not know :)
So I thought that I was obviously wrong and I should use
(Year year: 2016) daysInMonth
> "#(31 28 31 30 31 30 31 31 30 31 30 31)"
:(
When I look at the implementation this is clear that it is wrong
daysInMonths
^ Date daysInMonth
totally not aware of the year.
I think that daysInMonths should use DateAndTime creating a dummy date
for each month and using asMonth daysInMonth
(DateAndTime
year: 2016 month: 2 day: 3)
asMonth
daysInMonth
> 29
Year >> daysInMonth: aMonthNumber
"Returns the days in month for a given month"
<expr: #(#(#Year #year: 2016) #daysInMonth: 2) result: 29>
^ (DateAndTime year: self year month: aMonthNumber) asMonth daysInMonth
I extended the class with some more practical methods. What do you
think? I should push them to pharo?
I was surprised that the library was not that good.
Stef
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