Hi sven
I read the class comments in fact :)
and now rereading and your answer I start to understand.
What the class comments did not convey to me was that you have to
follow the 2001 example.
The "#reference timestamp" was confusing to me. I could not
undersrtand why you where talking about a method (that does not exist
in fact). Then I could not understand how the numbering of the
component of the example where related to the example you give below.
And I can tell you that I browse the class side accessing but I could
not find a simple date pattern.
By the way using a number higher than 12 for days could help
identifying the day from the month.
And now I see that as I expected we can also pass a date and not be
forced to pass a
(ZTimestampFormat fromString: '03/02/2001') format: Date today.
If you are interested I can try to propose a better class comment.
And BTW I already used the formatter but more than one year ago.
Stef
On Sun, Oct 22, 2017 at 11:00 PM, Sven Van Caekenberghe <
[hidden email]> wrote:
> Hi Stef,
>
>> On 22 Oct 2017, at 17:45, Stephane Ducasse <
[hidden email]> wrote:
>>
>> Hi sven
>>
>> I'm confused
>>
>> ft := ZTimestampFormat fromString: '02/11/2017'.
>> ft format: DateAndTime now
>>
>> produces 10/11/1017060986
>>
>> While I do not want time but just the date.
>> and the date is wrong.
>>
>> So I will do it manually but I found sad that ZTimestampFormat cannot
>> handle just handling days.
>> I could then pass also a date and it would not ask for nanoseconds.
>>
>> Stef
>
> ZTimestampFormat works with example based format specifications. This works by making each component unique, using a sequential number. Consult the class comment for a full explanation. The class side's #formatSpecifications lists the tokens that are understood and their meaning.
>
> To go back to your issue, The year is the first component, written as 2001, the month the third and the day the second. So you probably want to do:
>
> (ZTimestampFormat fromString: '03/02/2001') format: DateAndTime now.
>
> => '22/10/2017'
>
> HTH,
>
> Sven
>
>
>
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