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Don't understand Array creation syntax

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frankl1_miky

Don't understand Array creation syntax

Why the first element of #( ( 1 + 2 ) . 3 ) is #(1 #+ 2) and not #'('.
Thanks!!

Damien Pollet-2

Re: Don't understand Array creation syntax

That's just how the syntax is; it allows to have arrays as elements of arrays.

Also, to be coherent with what you thought, closing parentheses would have to become elements as well, and the array would never end.

On 12 June 2016 at 05:23, Franklin Mike <[hidden email]> wrote:

Why the first element of #( ( 1 + 2 ) . 3 ) is #(1 #+ 2) and not #'('.
Thanks!!

frankl1_miky

Re: Don't understand Array creation syntax

So if I understood it well, closing Parenthesis are telling that it's the same element in the Array

Damien Pollet-2

Re: Don't understand Array creation syntax

I don't understand what you've understood…

Parentheses need to be paired for the outer literal array to be recognized.

Technically, opening parentheses could become elements, but not closing parentheses, since then there would be nothing to close the literal array. And it would be strange to read if you could have several ((( but only one ) at the end.

Instead, pairs of parentheses enclose an array, which is nice because it makes it possible to have literal arrays as elements inside literal arrays. If you want a single parenthesis as an element, you have to explicitly write is using the symbol syntax.

On 14 June 2016 at 12:14, frankl1_miky <[hidden email]> wrote:

So if I understood it well, closing Parenthesis are telling that it's the
same element in the Array

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frankl1_miky

Re: Don't understand Array creation syntax

Thanks