Some questions
Locked
 
|
Hello,
I have two simple questions. In the code below: public MemberTypeBinding(char[][] compoundName, ClassScope scope, SourceTypeBinding enclosingType) { super(compoundName, scope, enclosingType); ... } How many Accesses and References do I have? (do the parameters contain 2 References and the super 3 Accesses). Thanks! -- Andre Hora _______________________________________________ Moose-dev mailing list [hidden email] https://www.iam.unibe.ch/mailman/listinfo/moose-dev |
|
|
Hi,
You get 0 references, and 3 accesses generated by the super call. The only question if there should be another access to the implicit variable "this". The types available in the method signature appear as declaredType, not as a reference. Cheers, Doru On 1 Nov 2011, at 10:46, Andre Hora wrote: > Hello, > > I have two simple questions. In the code below: > > public MemberTypeBinding(char[][] compoundName, ClassScope scope, SourceTypeBinding enclosingType) { > super(compoundName, scope, enclosingType); > ... > } > > How many Accesses and References do I have? (do the parameters contain 2 References and the super 3 Accesses). > > Thanks! > > -- > Andre Hora > > _______________________________________________ > Moose-dev mailing list > [hidden email] > https://www.iam.unibe.ch/mailman/listinfo/moose-dev -- www.tudorgirba.com "One cannot do more than one can do." _______________________________________________ Moose-dev mailing list [hidden email] https://www.iam.unibe.ch/mailman/listinfo/moose-dev |
|
|
On Tue, Nov 1, 2011 at 11:04 AM, Tudor Girba <[hidden email]> wrote: Hi, OK. A two months VerveineJ mse does not produce that (just two accesses from other parts of the method, but 0 from the super).
OK. So if I want to check my providers classes, I need to check Access, Reference, Inheritance, Invocation + check manually the types method signatures (parameters and return if the case)?
Thanks Doru,
-- Andre Hora _______________________________________________ Moose-dev mailing list [hidden email] https://www.iam.unibe.ch/mailman/listinfo/moose-dev |
|
|
Hi,
That is a problem. Could you create a small example java class and create an issue? Like that we can use it as a test fixture.
Yes. Doru
_______________________________________________ Moose-dev mailing list [hidden email] https://www.iam.unibe.ch/mailman/listinfo/moose-dev |
|
|
In reply to this post by Tudor Girba-2
Why 0 references? ClassScope and SourceTypeBinding are 2 references.
Alexandre On 1 Nov 2011, at 07:04, Tudor Girba wrote: > Hi, > > You get 0 references, and 3 accesses generated by the super call. The only question if there should be another access to the implicit variable "this". > > The types available in the method signature appear as declaredType, not as a reference. > > Cheers, > Doru > > > On 1 Nov 2011, at 10:46, Andre Hora wrote: > >> Hello, >> >> I have two simple questions. In the code below: >> >> public MemberTypeBinding(char[][] compoundName, ClassScope scope, SourceTypeBinding enclosingType) { >> super(compoundName, scope, enclosingType); >> ... >> } >> >> How many Accesses and References do I have? (do the parameters contain 2 References and the super 3 Accesses). >> >> Thanks! >> >> -- >> Andre Hora >> >> _______________________________________________ >> Moose-dev mailing list >> [hidden email] >> https://www.iam.unibe.ch/mailman/listinfo/moose-dev > > -- > www.tudorgirba.com > > "One cannot do more than one can do." > > > > > _______________________________________________ > Moose-dev mailing list > [hidden email] > https://www.iam.unibe.ch/mailman/listinfo/moose-dev -- _,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;: Alexandre Bergel http://www.bergel.eu ^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;. _______________________________________________ Moose-dev mailing list [hidden email] https://www.iam.unibe.ch/mailman/listinfo/moose-dev |
|
|
FAMIXReference refers to the class being a receiver of an invocation or an access.
As I said, the type declaration appears as a declaredType property of the method or variable. Cheers, Doru On 1 Nov 2011, at 14:01, Alexandre Bergel wrote: > Why 0 references? ClassScope and SourceTypeBinding are 2 references. > > Alexandre > > > On 1 Nov 2011, at 07:04, Tudor Girba wrote: > >> Hi, >> >> You get 0 references, and 3 accesses generated by the super call. The only question if there should be another access to the implicit variable "this". >> >> The types available in the method signature appear as declaredType, not as a reference. >> >> Cheers, >> Doru >> >> >> On 1 Nov 2011, at 10:46, Andre Hora wrote: >> >>> Hello, >>> >>> I have two simple questions. In the code below: >>> >>> public MemberTypeBinding(char[][] compoundName, ClassScope scope, SourceTypeBinding enclosingType) { >>> super(compoundName, scope, enclosingType); >>> ... >>> } >>> >>> How many Accesses and References do I have? (do the parameters contain 2 References and the super 3 Accesses). >>> >>> Thanks! >>> >>> -- >>> Andre Hora >>> >>> _______________________________________________ >>> Moose-dev mailing list >>> [hidden email] >>> https://www.iam.unibe.ch/mailman/listinfo/moose-dev >> >> -- >> www.tudorgirba.com >> >> "One cannot do more than one can do." >> >> >> >> >> _______________________________________________ >> Moose-dev mailing list >> [hidden email] >> https://www.iam.unibe.ch/mailman/listinfo/moose-dev > > -- > _,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;: > Alexandre Bergel http://www.bergel.eu > ^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;. > > > > > > _______________________________________________ > Moose-dev mailing list > [hidden email] > https://www.iam.unibe.ch/mailman/listinfo/moose-dev -- www.tudorgirba.com "If you interrupt the barber while he is cutting your hair, you will end up with a messy haircut." _______________________________________________ Moose-dev mailing list [hidden email] https://www.iam.unibe.ch/mailman/listinfo/moose-dev |
«
Return to Moose
|
1 view|%1 views
| Free forum by Nabble | Edit this page |