On 26.11.2010, at 18:09, Andres Valloud wrote: > Can you assume that allocation is sequential? I can. - Bert - > On 11/26/10 8:59 , Bert Freudenberg wrote: >> >> On 26.11.2010, at 17:43, Andres Valloud wrote: >> >>>> You *must* use an end marker, i.e., >>>> >>>> last := Object new. "end marker" >>>> obj := self someObject. >>>> [last == obj] whileFalse:[ >>>> count := count + 1. >>>> obj := obj nextObject. >>>> ]. >>>> >>>> This will work because it counts between the beginning of memory and the >>>> (arbitrary) end marker. Anything else basically should not be relied on >>>> to work, jit or no. >>> >>> What happens if a process with higher priority interrupts the iteration and creates more objects? >> >> New objects would come after the end marker in memory. >> >> - Bert - |
I'm not familiar with Squeak's GC... can you also assume that a GC
(e.g.: a "new space" scavenge) won't move the marker so that the enumeration goes past it? On 11/26/10 9:12 , Bert Freudenberg wrote: > > On 26.11.2010, at 18:09, Andres Valloud wrote: > >> Can you assume that allocation is sequential? > > I can. > > - Bert - > >> On 11/26/10 8:59 , Bert Freudenberg wrote: >>> >>> On 26.11.2010, at 17:43, Andres Valloud wrote: >>> >>>>> You *must* use an end marker, i.e., >>>>> >>>>> last := Object new. "end marker" >>>>> obj := self someObject. >>>>> [last == obj] whileFalse:[ >>>>> count := count + 1. >>>>> obj := obj nextObject. >>>>> ]. >>>>> >>>>> This will work because it counts between the beginning of memory and the >>>>> (arbitrary) end marker. Anything else basically should not be relied on >>>>> to work, jit or no. >>>> >>>> What happens if a process with higher priority interrupts the iteration and creates more objects? >>> >>> New objects would come after the end marker in memory. >>> >>> - Bert - > > > |
On Fri, Nov 26, 2010 at 9:15 AM, Andres Valloud <[hidden email]> wrote: I'm not familiar with Squeak's GC... can you also assume that a GC (e.g.: a "new space" scavenge) won't move the marker so that the enumeration goes past it? IIUC, that's irrelevant. FOr the marker technique to work all that's needed is that the relative order of live objects isn't changed. The only thing that can change that is a become:. In the absence of a become: the end marker, no matter how many GCs occur, stays above/after all previously activated objects and below/before all subsequently allocated objects. The Squeak GC effectively only compacts to squeeze out reclaimed objects, it does not reorder. So this is very different to the VM/HPS GC.
HTH Eliot
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Yes, from what I've seen, Squeak's GC is different from that in HPS. I
found some information scattered here and there in Google, but it's mostly commentary. Ideally, I'd look at the source code and figure it out but I don't quite have the time to look at it in all its detail. I would really appreciate a current, 3-5 sentence summary of Squeak's GC implementation. Does anyone have such a pointer? I hope this request is not deemed ridiculous, I'm thinking it would be just as unreasonable to expect anybody to look at HPS' GC implementation and get the gist of what's going on in 5-10 minutes. Thanks in advance! On 11/27/10 14:06 , Eliot Miranda wrote: > > > On Fri, Nov 26, 2010 at 9:15 AM, Andres Valloud > <[hidden email] > <mailto:[hidden email]>> wrote: > > I'm not familiar with Squeak's GC... can you also assume that a GC > (e.g.: a "new space" scavenge) won't move the marker so that the > enumeration goes past it? > > > IIUC, that's irrelevant. FOr the marker technique to work all that's > needed is that the relative order of live objects isn't changed. The > only thing that can change that is a become:. In the absence of a > become: the end marker, no matter how many GCs occur, stays above/after > all previously activated objects and below/before all subsequently > allocated objects. The Squeak GC effectively only compacts to squeeze > out reclaimed objects, it does not reorder. So this is very different > to the VM/HPS GC. > > HTH > Eliot > > > > On 11/26/10 9:12 , Bert Freudenberg wrote: > > > On 26.11.2010, at 18:09, Andres Valloud wrote: > > Can you assume that allocation is sequential? > > > I can. > > - Bert - > > On 11/26/10 8:59 , Bert Freudenberg wrote: > > > On 26.11.2010, at 17:43, Andres Valloud wrote: > > You *must* use an end marker, i.e., > > last := Object new. "end marker" > obj := self someObject. > [last == obj] whileFalse:[ > count := count + 1. > obj := obj nextObject. > ]. > > This will work because it counts between the > beginning of memory and the > (arbitrary) end marker. Anything else basically > should not be relied on > to work, jit or no. > > > What happens if a process with higher priority > interrupts the iteration and creates more objects? > > > New objects would come after the end marker in memory. > > - Bert - > > > > > > |
http://stephane.ducasse.free.fr/FreeBooks/CollectiveNBlueBook/Rowledge-Final.pdf
On pp. 20 it has an excellent summary about how the Squeak GC works. Cheers, - Andreas On 11/30/2010 4:13 PM, Andres Valloud wrote: > Yes, from what I've seen, Squeak's GC is different from that in HPS. I > found some information scattered here and there in Google, but it's > mostly commentary. Ideally, I'd look at the source code and figure it > out but I don't quite have the time to look at it in all its detail. I > would really appreciate a current, 3-5 sentence summary of Squeak's GC > implementation. Does anyone have such a pointer? I hope this request is > not deemed ridiculous, I'm thinking it would be just as unreasonable to > expect anybody to look at HPS' GC implementation and get the gist of > what's going on in 5-10 minutes. Thanks in advance! > > On 11/27/10 14:06 , Eliot Miranda wrote: >> >> >> On Fri, Nov 26, 2010 at 9:15 AM, Andres Valloud >> <[hidden email] >> <mailto:[hidden email]>> wrote: >> >> I'm not familiar with Squeak's GC... can you also assume that a GC >> (e.g.: a "new space" scavenge) won't move the marker so that the >> enumeration goes past it? >> >> >> IIUC, that's irrelevant. FOr the marker technique to work all that's >> needed is that the relative order of live objects isn't changed. The >> only thing that can change that is a become:. In the absence of a >> become: the end marker, no matter how many GCs occur, stays above/after >> all previously activated objects and below/before all subsequently >> allocated objects. The Squeak GC effectively only compacts to squeeze >> out reclaimed objects, it does not reorder. So this is very different >> to the VM/HPS GC. >> >> HTH >> Eliot >> >> >> >> On 11/26/10 9:12 , Bert Freudenberg wrote: >> >> >> On 26.11.2010, at 18:09, Andres Valloud wrote: >> >> Can you assume that allocation is sequential? >> >> >> I can. >> >> - Bert - >> >> On 11/26/10 8:59 , Bert Freudenberg wrote: >> >> >> On 26.11.2010, at 17:43, Andres Valloud wrote: >> >> You *must* use an end marker, i.e., >> >> last := Object new. "end marker" >> obj := self someObject. >> [last == obj] whileFalse:[ >> count := count + 1. >> obj := obj nextObject. >> ]. >> >> This will work because it counts between the >> beginning of memory and the >> (arbitrary) end marker. Anything else basically >> should not be relied on >> to work, jit or no. >> >> >> What happens if a process with higher priority >> interrupts the iteration and creates more objects? >> >> >> New objects would come after the end marker in memory. >> >> - Bert - >> >> >> >> >> >> > > |
Awesome, thank you! That makes the "marker technique" more clear. In
HPS parlance (excuse me using the terminology I am most familiar with), Squeak has an eden plus two survivor semi spaces, and old space for the rest. The incremental GC would be a scavenge of new space. The full GC is a mark / sweep GC of all object data. Does that make sense? Also, would you mind a question? If the new objects are above the old data, what happens when the old data grows large enough that it runs into the new object space? Is the new object space moved upwards? On 11/30/10 16:20 , Andreas Raab wrote: > http://stephane.ducasse.free.fr/FreeBooks/CollectiveNBlueBook/Rowledge-Final.pdf > > On pp. 20 it has an excellent summary about how the Squeak GC works. > > Cheers, > - Andreas > > On 11/30/2010 4:13 PM, Andres Valloud wrote: >> Yes, from what I've seen, Squeak's GC is different from that in HPS. I >> found some information scattered here and there in Google, but it's >> mostly commentary. Ideally, I'd look at the source code and figure it >> out but I don't quite have the time to look at it in all its detail. I >> would really appreciate a current, 3-5 sentence summary of Squeak's GC >> implementation. Does anyone have such a pointer? I hope this request is >> not deemed ridiculous, I'm thinking it would be just as unreasonable to >> expect anybody to look at HPS' GC implementation and get the gist of >> what's going on in 5-10 minutes. Thanks in advance! >> >> On 11/27/10 14:06 , Eliot Miranda wrote: >>> >>> >>> On Fri, Nov 26, 2010 at 9:15 AM, Andres Valloud >>> <[hidden email] >>> <mailto:[hidden email]>> wrote: >>> >>> I'm not familiar with Squeak's GC... can you also assume that a GC >>> (e.g.: a "new space" scavenge) won't move the marker so that the >>> enumeration goes past it? >>> >>> >>> IIUC, that's irrelevant. FOr the marker technique to work all that's >>> needed is that the relative order of live objects isn't changed. The >>> only thing that can change that is a become:. In the absence of a >>> become: the end marker, no matter how many GCs occur, stays above/after >>> all previously activated objects and below/before all subsequently >>> allocated objects. The Squeak GC effectively only compacts to squeeze >>> out reclaimed objects, it does not reorder. So this is very different >>> to the VM/HPS GC. >>> >>> HTH >>> Eliot >>> >>> >>> >>> On 11/26/10 9:12 , Bert Freudenberg wrote: >>> >>> >>> On 26.11.2010, at 18:09, Andres Valloud wrote: >>> >>> Can you assume that allocation is sequential? >>> >>> >>> I can. >>> >>> - Bert - >>> >>> On 11/26/10 8:59 , Bert Freudenberg wrote: >>> >>> >>> On 26.11.2010, at 17:43, Andres Valloud wrote: >>> >>> You *must* use an end marker, i.e., >>> >>> last := Object new. "end marker" >>> obj := self someObject. >>> [last == obj] whileFalse:[ >>> count := count + 1. >>> obj := obj nextObject. >>> ]. >>> >>> This will work because it counts between the >>> beginning of memory and the >>> (arbitrary) end marker. Anything else basically >>> should not be relied on >>> to work, jit or no. >>> >>> >>> What happens if a process with higher priority >>> interrupts the iteration and creates more objects? >>> >>> >>> New objects would come after the end marker in memory. >>> >>> - Bert - >>> >>> >>> >>> >>> >>> >> >> > > > . > |
On Tue, Nov 30, 2010 at 6:38 PM, Andres Valloud <[hidden email]> wrote: Awesome, thank you! That makes the "marker technique" more clear. In HPS parlance (excuse me using the terminology I am most familiar with), Squeak has an eden plus two survivor semi spaces, and old space for the rest. The incremental GC would be a scavenge of new space. The full GC is a mark / sweep GC of all object data. Does that make sense? Yes. Also, would you mind a question? If the new objects are above the old data, what happens when the old data grows large enough that it runs into the new object space? Is the new object space moved upwards? Think of the heap (including new space) as one region growing towards a limit. Old space is immediately below new space, a single variable pointing to the boundary. Somewhere above that is the allocation pointer. When one does a tenuring incremental collection new space is compacted and the pointer to the top of old space merely set to point to teh allocation pointer, so now everything is old. By the same token, to do a full gc the old space pointer is merely set to the bottom of the heap, so now everything is young, and the roots are the active context and the special objects array.
Unlinke HPS there is no such thing as an old space allocation, because there is no free list of free old space objects, and because old space and new space are contiguous. Hence a large allocation will typically tenure everything.
Make sense? best Eliot
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Yes, that does make sense. Thank you :).
On 11/30/10 18:45 , Eliot Miranda wrote: > > > On Tue, Nov 30, 2010 at 6:38 PM, Andres Valloud > <[hidden email] > <mailto:[hidden email]>> wrote: > > Awesome, thank you! That makes the "marker technique" more clear. > In HPS parlance (excuse me using the terminology I am most > familiar with), Squeak has an eden plus two survivor semi spaces, > and old space for the rest. The incremental GC would be a scavenge > of new space. The full GC is a mark / sweep GC of all object data. > Does that make sense? > > > Yes. > > Also, would you mind a question? If the new objects are above the > old data, what happens when the old data grows large enough that it > runs into the new object space? Is the new object space moved upwards? > > > Think of the heap (including new space) as one region growing towards a > limit. Old space is immediately below new space, a single variable > pointing to the boundary. Somewhere above that is the allocation > pointer. When one does a tenuring incremental collection new space is > compacted and the pointer to the top of old space merely set to point to > teh allocation pointer, so now everything is old. By the same token, to > do a full gc the old space pointer is merely set to the bottom of the > heap, so now everything is young, and the roots are the active context > and the special objects array. > Unlinke HPS there is no such thing as an old space allocation, because > there is no free list of free old space objects, and because old space > and new space are contiguous. Hence a large allocation will typically > tenure everything. > > Make sense? > > best > Eliot > > > > On 11/30/10 16:20 , Andreas Raab wrote: > > http://stephane.ducasse.free.fr/FreeBooks/CollectiveNBlueBook/Rowledge-Final.pdf > > On pp. 20 it has an excellent summary about how the Squeak GC works. > > Cheers, > - Andreas > > On 11/30/2010 4:13 PM, Andres Valloud wrote: > > Yes, from what I've seen, Squeak's GC is different from that > in HPS. I > found some information scattered here and there in Google, > but it's > mostly commentary. Ideally, I'd look at the source code and > figure it > out but I don't quite have the time to look at it in all its > detail. I > would really appreciate a current, 3-5 sentence summary of > Squeak's GC > implementation. Does anyone have such a pointer? I hope this > request is > not deemed ridiculous, I'm thinking it would be just as > unreasonable to > expect anybody to look at HPS' GC implementation and get the > gist of > what's going on in 5-10 minutes. Thanks in advance! > > On 11/27/10 14:06 , Eliot Miranda wrote: > > > > On Fri, Nov 26, 2010 at 9:15 AM, Andres Valloud > <[hidden email] > <mailto:[hidden email]> > <mailto:[hidden email] > <mailto:[hidden email]>>> wrote: > > I'm not familiar with Squeak's GC... can you also assume > that a GC > (e.g.: a "new space" scavenge) won't move the marker so > that the > enumeration goes past it? > > > IIUC, that's irrelevant. FOr the marker technique to > work all that's > needed is that the relative order of live objects isn't > changed. The > only thing that can change that is a become:. In the > absence of a > become: the end marker, no matter how many GCs occur, > stays above/after > all previously activated objects and below/before all > subsequently > allocated objects. The Squeak GC effectively only > compacts to squeeze > out reclaimed objects, it does not reorder. So this is > very different > to the VM/HPS GC. > > HTH > Eliot > > > > On 11/26/10 9:12 , Bert Freudenberg wrote: > > > On 26.11.2010, at 18:09, Andres Valloud wrote: > > Can you assume that allocation is sequential? > > > I can. > > - Bert - > > On 11/26/10 8:59 , Bert Freudenberg wrote: > > > On 26.11.2010, at 17:43, Andres Valloud wrote: > > You *must* use an end marker, i.e., > > last := Object new. "end marker" > obj := self someObject. > [last == obj] whileFalse:[ > count := count + 1. > obj := obj nextObject. > ]. > > This will work because it counts between the > beginning of memory and the > (arbitrary) end marker. Anything else basically > should not be relied on > to work, jit or no. > > > What happens if a process with higher priority > interrupts the iteration and creates more objects? > > > New objects would come after the end marker in memory. > > - Bert - > > > > > > > > > > > . > > > |
In reply to this post by Levente Uzonyi-2
On Tue, Nov 16, 2010 at 9:52 PM, Levente Uzonyi <[hidden email]> wrote:
I would like to reserve this for a page of new bytecodes, some of which I'd like to use for adaptive optimization/speculative inlining work that Marcus, Colin and I are planning to start in the new year.
best Eliot
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