#(16 17 17 16 18 17 18 19 19 19 18 19 19 20 19 20 19 20 20 20 19 20)
-> { #(17 17 16 18 17 18 19) . #(19 19 18 19 19 20 19) . #(20 19 20 20 20 19 20)} any code? |
The first thing I found:
#(16 17 17 16 18 17 18 19 19 19 18 19 19 20 19 20 19 20 20 20 19 20) groupsOf: 7 atATimeCollect: [ :x | x ] "#(#(16 17 17 16 18 17 18) #(19 19 19 18 19 19 20) #(19 20 19 20 20 20 19))" > On 25 Apr 2017, at 22:08, Stephane Ducasse <[hidden email]> wrote: > > #(16 17 17 16 18 17 18 19 19 19 18 19 19 20 19 20 19 20 20 20 19 20) > > -> > > { #(17 17 16 18 17 18 19) . #(19 19 18 19 19 20 19) . #(20 19 20 20 20 19 20)} > > any code? |
#(16 17 17 16 18 17 18 19 19 19 18 19 19 20 19 20 19 20 20 20 19 20) allButFirst groupsOf: 7 atATimeCollect: [ :element | element ].
Nacho
Smalltalker apprentice.
Buenos Aires, Argentina.
|
In reply to this post by Stephane Ducasse-3
In 2003, I implemented the following method. It is something
that comes up from time to time.
!SequenceableCollection publicMethods !
splitEvery: chunkSize
"Answer a collection of sub-collections each of the specified chunk size. If the receiver size is not a multiple of chunkSize, the last sub-collection will be shorter." | chunks stream |
chunkSize < 1 ifTrue: [ ^self splitEvery: 1 ]. stream := ReadStream on: self.
chunks := OrderedCollection new. [stream atEnd] whileFalse: [ chunks add: (stream nextOrLess: chunkSize). ]. ^chunks. ! ! From: Pharo-users [mailto:[hidden email]] On Behalf Of Stephane Ducasse Sent: April 25, 2017 13:08 To: Any question about pharo is welcome Subject: [Pharo-users] little "challenge" #(16 17 17 16 18 17 18 19 19 19 18 19 19
20 19 20 19 20 20 20 19 20)
->
{ #(17 17 16 18 17 18 19) . #(19 19 18 19 19 20 19) . #(20 19 20 20 20 19
20)}
any code? |
In reply to this post by Sven Van Caekenberghe-2
I did not know this one :) tx sven On Tue, Apr 25, 2017 at 10:26 PM, Sven Van Caekenberghe <[hidden email]> wrote: The first thing I found: |
In reply to this post by nacho
Tx same comments! On Tue, Apr 25, 2017 at 10:48 PM, nacho <[hidden email]> wrote: #(16 17 17 16 18 17 18 19 19 19 18 19 19 20 19 20 19 20 20 20 19 20) |
In reply to this post by Richard Sargent (again)
This is fun because my method was called splitEvery: too :) On Wed, Apr 26, 2017 at 6:19 AM, Richard Sargent <[hidden email]> wrote:
|
In reply to this post by Richard Sargent (again)
we do not have nextOrLess: in Pharo. On Wed, Apr 26, 2017 at 6:19 AM, Richard Sargent <[hidden email]> wrote:
|
Sorry, Stephane. Feel free to implement missing methods (or their equivalent).
:-)
On Apr 25, 2017, at 23:39, Stephane Ducasse <[hidden email]> wrote:
|
In reply to this post by Stephane Ducasse-3
Doesn't matter as next returns if there is less than required. groups := OrderedCollection new. input := (String loremIpsum: 20). input readStream in: [ :s | [s atEnd] whileFalse: [ groups add: (s next: 7) ]]. groups. Interestingly loremIpsum: adds Character cr to from paragraphs (output looked strange at first glance). Phil On Wed, Apr 26, 2017 at 8:38 AM, Stephane Ducasse <[hidden email]> wrote:
|
In reply to this post by Stephane Ducasse-3
I implemented it for fun and noticed that in your test data, the first 16 is gone. So, groupings are wrong with all methods proposed in a sense. With Richard's version, we get this in Pharo #(16 17 17 16 18 17 18 19 19 19 18 19 19 20 19 20 19 20 20 20 19 20) splitEvery: 7 "an OrderedCollection(#(16 17 17 16 18 17 18) #(19 19 19 18 19 19 20) #(19 20 19 20 20 20 19) #(20))" splitEvery: chunkSize "Answer a collection of sub-collections each of the specified chunk size. If the receiver size is not a multiple of chunkSize, the last sub-collection will be shorter." | chunks stream | chunkSize < 1 ifTrue: [ ^self splitEvery: 1 ]. stream := ReadStream on: self. chunks := OrderedCollection new. [stream atEnd] whileFalse: [ chunks add: (stream next: chunkSize). ]. ^chunks. Phil On Wed, Apr 26, 2017 at 8:38 AM, Stephane Ducasse <[hidden email]> wrote:
|
In reply to this post by Stephane Ducasse-3
Now I fully got the implementation " #(16 17 17 16 18 17 18 19 19 19 18 19 19 20 19 20 19 20 20 20 19 20) groupsOf: 7 atATimeCollect: [ :x | x ] >>> #(#(16 17 17 16 18 17 18) #(19 19 19 18 19 19 20) #(19 20 19 20 20 20 19)) " " #(1 1 1 10 10 10 100 100 100) groupsOf: 3 atATimeCollect: [ :x :y :z | x + y + z] >>> #(3 30 300) " " #(1 1 1 10 10 10 100 100 100) groupsOf: 3 atATimeCollect: [ :x | x ] >>> #(#(1 1 1) #(10 10 10) #(100 100 100)) " On Wed, Apr 26, 2017 at 8:38 AM, Stephane Ducasse <[hidden email]> wrote:
|
So the last 20 is left out. Correct? Phil On Wed, Apr 26, 2017 at 11:20 AM, Stephane Ducasse <[hidden email]> wrote:
|
splitEvery: n ^ (n to: self size by: n) collect: [:index | (self copyFrom: index - n + 1 to: index)] is my solution On Wed, Apr 26, 2017 at 11:34 AM, [hidden email] <[hidden email]> wrote:
|
Free forum by Nabble | Edit this page |