[vwnc] ComboBox Display String Fails

To find an employee in the list, you have to use the same string representation to find him, that you also use to convert the object to a string.

If you print with (self name ifNil: [''] ), '  ' , '---' ,self empNo.), your detect block must use the same construct to find this string representation in the list:
  detect: [:each | ((each name ifNil: [''] ), '  ' , '---' ,each empNo) = aString].

Or, because you wrote that in the specific method #displayString, change the detect to:
  detect: [:each | each displayString = aString].

HTH

Thomas


Juan Pablo Cook schrieb:

Thanks for your reply!
I try and now it works! ;)
I put this:

^(self name ifNil: [''] ), '  ' , '---' ,self empNo.

Now I have 2 problems I think:

First one is, when I open the window, it's nothing selected so it's show , '  ' , '---', this strings.
Second one, is that the #stringToEmployee now doesn't work because don't recognize the object. This is the method:

#stringToEmployee: aString
| emp |
emp := self employeeList value
detect: [:each | each name = aString]
ifNone: [nil].

^ciud

How can I change that?

Thanks again for your help.

Hugs,
JP Cook

On Wed, Jun 24, 2009 at 4:21 AM, Mark Plas <[hidden email] <mailto:[hidden email]>> wrote:

   Could it be that the employee's name is nil? in that case sending
   ',' to it won't work.
       You could try this:
       displayString
          ^(self name ifNil: ['']),'  ','---',empNo.



   *From:* [hidden email] <mailto:[hidden email]>
   [mailto:[hidden email]
   <mailto:[hidden email]>] *On Behalf Of *Juan Pablo Cook
   *Sent:* dinsdag 23 juni 2009 22:54

   *To:* Richard Wettel; [hidden email] <mailto:[hidden email]>

   *Subject:* Re: [vwnc] ComboBox Display String Fails
       Thanks for your reply, I put that like an example, in that case
   empNo is a string.
   But the problem it's before, nothing works because the ,' after
   name don't work.
   What can I do?

   Thanks
   On Tue, Jun 23, 2009 at 5:44 PM, Richard Wettel

   <[hidden email] <mailto:[hidden email]>>

   wrote:
   Hi,
       It's just a guess, but if empNo is not a string you won't be able
   to append it as is to another string. For example if empNo is a
   number, you need to send printString to it to get a string
   representation of the number.
       Cheers,
   Ricky
       On Jun 23, 2009, at 10:18 PM, Juan Pablo Cook wrote:
   
       Hi All!! I'm looking for your help because it doesn't work
       what I want to do, I don't know why.
       I read the Vw Docs and see the videos of James:
       http://www.cincomsmalltalk.com/blog/blogView?showComments=true&printTitle=Smalltalk_Daily_11/14/08:_The_ComboBox_Widget&entry=3404103177
       <http://www.cincomsmalltalk.com/blog/blogView?showComments=true&printTitle=Smalltalk_Daily_11/14/08:_The_ComboBox_Widget&entry=3404103177>
       and
       http://www.cincomsmalltalk.com/blog/blogView?showComments=true&printTitle=Smalltalk_Daily_11/17/08:_ComboBox_Widget_Part_2&entry=3404359439
       <http://www.cincomsmalltalk.com/blog/blogView?showComments=true&printTitle=Smalltalk_Daily_11/17/08:_ComboBox_Widget_Part_2&entry=3404359439>.
       So I have a comboBox where the type property is set to Object.
       The read method is: #stringToEmployee: and print:
       #employeeToString: .
       First I have this:

       #employeeToString: anEmployee
             ^anEmployee name

       And works perfect, but later I want to add something to that
       string, so James told me that I have to define the
       #displayString method in the Employee class. I did all.
       Now I have:

       #employeeToString: anEmployee
              ^anEmployee displayString.

       Employee Class:
       #displayString
              ^self name,'  ','---',empNo.

       And this fails, the error says " #, " so I can't join nothing
       to the string.

       I hope someone knows my "stupid" problem that I can't resolve.

       Thanks a lot

       JP Cook

       <ATT00001.txt>
       

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